The standard reduction potential at `25^(@)C` of the reaction `2H_(2)O+2e^(-) rarr H_(2)+2OH^(-)` is -0.8277 volt. Calculate the equuilibrium constant for the reaction, `2H_(2)O hArr H_(3)O^(+)+OH^(-)` at `25^(@)C`

The standard reduction potential at `25^(@)C` of the reaction `2H_(2)O

1.	The standard reduction potential at `25^(@)C` of the reaction `2H_(2)O+2e^(-) rarr H_(2)+2OH^(-)` is -0.8277 volt. Calculate the equuilibrium constant for the reaction, `2H_(2)O hArr H_(3)O^(+)+OH^(-)` at `25^(@)C`
Answer» Correct Answer - `~~10^(14)` `H_(2)O+e^(-) rarr ½H_(2)+OH^(-) ("Cathode"), E^(@)=-0.8277` volt `H_(2)O + ½H_(2) rarr H_(3)O^(+)+e^(-) " (Anode)", E^(@)=0` `E^(@)` for the cell `=-0.8277` volt Apply now `E^(@)=.0591/n [log K]" "(n=1)`

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The standard reduction potential at `25^(@)C` of the reaction `2H_(2)O+2e^(-) rarr H_(2)+2OH^(-)` is -0.8277 volt. Calculate the equuilibrium constant for the reaction, `2H_(2)O hArr H_(3)O^(+)+OH^(-)` at `25^(@)C`

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