1.

The standard reduction potential for Cu^(2+)//Cu is +0.34V. Calculate the reduction potential at pH=14 for the above couple. K_(SP) of Cu(OH)_(2) is 1.0xx10^(-19)

Answer»

2.2 V
3.4 V
`-0.22` V
`-2.2` V

Solution :`pH=-log[H^+]=14 rArr [H^+]=10^(-14)`
Hence, `[OH^-]=1M [H^+][OH^-]=10^(-4)`
`CU(OH)_2 to Cu^(2+) + 2OH^-`
`K_"SP"=[Cu^(2+)][OH^-]^2`
For the REACTION, `Cu^(2+) + 2e^(-) to Cu , n=2`
`E_"cell"=E_"cell"^@-0.0591/n"log"1/([Cu^(2+)])`
`E_"cell"=0.34-0.0591/2"log"1/(1xx10^(-19))`=-0.22 V


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