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The standard reduction potential for two reactions are given below `AgCl(s)+e^(-)rarrAg(s)+Cl^(-)(aq) ,E^(@)=0.22V` `Ag^(+)(aq)+e^(-)rarrAg(s),E^(@)=0.80V` The solubility product of AgCl under standard conditions of temperature is given byA. `1.613 xx 10^(-5) M^(2)`B. `1.535 xx 10^(-8) M^(2)`C. `3.213 xx 10^(-10) M^(2)`D. `1.535 xx 10^(-10) M^(2)` |
Answer» Correct Answer - B From eqs. (i) and (ii) `AgCl(s) hArr Ag^(+)+Cl^(-), E^(@)=0.22-0.80=-0.58 V` `E_("cell")=E_("cell")^(@)-0.0591/2 log [Ag^(+)][Cl^(-)]` `0=-0.58-0.0591/2 log [Ag^(+)][Cl^(-)]` `K_(sp)=[Ag^(+)][Cl^(-)]=1.535xx10^(-10) M^(2)` |
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