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The standard reduction potential of `Cu^(+)//Cu` couple is 0.34 V at `25^(@)C` calculate the reduction potential at `pH=14` for this couple. (Given `K_(sp),Cu(OH)_(2)=1.0xx10^(-19)`)A. `-0.22` VB. `+0.22` VC. `-0.34` VD. `+0.34` V |
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Answer» Correct Answer - A `Cu^(2+) + 2e^(-) to Cu`, `E = E^(@) - (0.0592)/(2) log_(10) (1)/([Cu^(2+)])` `= 0.34 - (0.059)/(2) log_(10) ((1)/(10^(-19)))= - 0.22V`. |
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