1.

The standard reduction potential of the half -cell: NO_(3)^(-)(aq)+2H^(+)+e rarr NO_(2)(g)+H_(2)O is 0.78V. (1) Calculate the reduction potential in 8 M H^(+).

Answer»

Solution :Reaction :
`NO_(3)^(-)(aq)+2H^(+)(aq)+e rarr NO_(2)(g)+H_(2)O(l)`
`E_("CELL")=E_("cell")^(@)-(0.059)/(N)LOG.([NO_(2)][H_(2)O])/([NO_(3)^(-)][H^(+)]^(2))`
`=0.78-(0.059)/(1)log.(1xx1)/(1XX(8)^(2))=0.887V`


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