The state of an ideal gas is changed through an isothermal process at temperature `T_0` as shown in figure. The work done by the gas in going from state B to C is double the work done by gas in going from state A to B. If the pressure in the state B is `(p_0)/(2)`, then the pressure of the gas in state C is A. (a) `p_0/3`B. (b) `p_0/4`C. (c) `p_0/6`D. (d) `p_0/8`

The state of an ideal gas is changed through an isothermal process at

1.	The state of an ideal gas is changed through an isothermal process at temperature `T_0` as shown in figure. The work done by the gas in going from state B to C is double the work done by gas in going from state A to B. If the pressure in the state B is `(p_0)/(2)`, then the pressure of the gas in state C is A. (a) `p_0/3`B. (b) `p_0/4`C. (c) `p_0/6`D. (d) `p_0/8`
Answer» Correct Answer - D `W=nRT_01n((p_i)/(p_f))` `W_(BC)=2W_(AB)` `:.` `nRT_0 In((p_C)/(p_0//2))=2nRT_0 In((p_0//2)/(p_0))` Solving this equation we get, `p_C=p_0/8`

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