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The stationary wave`y = 2a sin kx cos omega t` in a closed organ pipe is the result of the superposition of `y = a sin (omega t - kx)`A. `y = a cos(omegat- kx)`B. `y = -a sin(omegat+ kx)`C. `y = a sin(omegat- kx)`D. `y = a cos(omegat+ kx)` |
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Answer» Correct Answer - D Potential across the capacitor is zero, hence energy stored is zero. |
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