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The strenth of 10 volume of H_(2)O_(2) solution is : |
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Answer» 10 `underset(68 g)(2H_(2)O_(2))to 2H_(2)O_underset(22.4 " L at STP")(O_(2))` `because 22.4 L O_(2)` is OBTAINED at STP from `68 g H_(2)O_(2)` `therefore L O_(2)` is obtained at STP from `(68)/(22.4)xx10 g H_(2)O_(2)` =30.36 g Thus, strength of `H_(2)O_(2)=30.36 g//L`. |
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