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The string of a guitar is 80 cm long and has a fundamental frequency of 112 Hz. If a guitarist wishes to produce a frequency of 160 Hz, where should the person press the string ? |
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Answer» Data : L1 = 80 cm n1 = 112 Hz, n2 = 160 Hz According to the law of length, n1L1 = n2L2 . ∴ The vibrating length to produce the fundamental frequency of 160 Hz, L2 = \(\frac{n_1L_1}{n_2}\) = \(\frac{112(80)}{160}\) = 56 cm |
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