The sublimation energy of I_(2)(s) is 57.3kJ // mol and the enthalpy of fusion is 15.5 kJ // mol. The enthalpy of vaporisationof I_(2) is

The sublimation energy of I_(2)(s) is 57.3kJ // mol and the enthalpy o

1.	The sublimation energy of I_(2)(s) is 57.3kJ // mol and the enthalpy of fusion is 15.5 kJ // mol. The enthalpy of vaporisationof I_(2) is
Answer» 41.8 kJ `//` MOL `-41.8 kJ //` mol 72.8 kJ`//` mol `-72.8 kJ // `mol Solution :`DeltaH_("SUB")= DeltaH_("fusion") + DELTAH _(vap)`