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The substance undergoes first order decomposition.The decomposition follows two parallel first order reactons as : `K_1=10^(-2) sec^(-1) and K_2=10^(-2)sec^(-1)` If the corresponding activation energies of parallel reaction are 100 and 120 kJ `"mol"^(-1)` then the net activation energy of A is/are:A. 120 kJ `"mol"^(-1)`B. 116 kJ `"mol"^(-1)`C. 100 kJ `"mol"^(-1)`D. 150 kJ `"mol"^(-1)` |
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Answer» Correct Answer - B `E=(k_1E_1+k_2E_2)/(k_1+k_2)=(10^(-2)xx100+120xx4xx10^(-2))/(10^(-2)+4xx10^(-2))=116 kJ mol^(-1)` |
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