1.

The substance undergoes first order decomposition.The decomposition follows two parallel first order reactons as : `K_1=10^(-2) sec^(-1) and K_2=10^(-2)sec^(-1)` If the corresponding activation energies of parallel reaction are 100 and 120 kJ `"mol"^(-1)` then the net activation energy of A is/are:A. 120 kJ `"mol"^(-1)`B. 116 kJ `"mol"^(-1)`C. 100 kJ `"mol"^(-1)`D. 150 kJ `"mol"^(-1)`

Answer» Correct Answer - B
`E=(k_1E_1+k_2E_2)/(k_1+k_2)=(10^(-2)xx100+120xx4xx10^(-2))/(10^(-2)+4xx10^(-2))=116 kJ mol^(-1)`


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