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The successive ionization energy values for an element X are given below: (1) 1st ionization energy = 410 kJ mol^(-1) (2) 2nd ionization energy = 820 kJ mol^(-1) (3) 3rd ionization energy = 1100kJ mol^(-1) (4) 4th ionization energy = 1500 kJ mol^(-1) (5) 5th ionization energy =3200 kJ mol^(-1) Find out the number of valence electrons for the atom X |
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Answer» 1st ionization energy =410 KJ `MOL^(-1)` |
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