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InterviewSolution
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The suitable condition for the emission of photoelectron with certain kinetic energy(A) v < VO(B) V > VO(C) υ = 0(D) All the above |
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Answer» A)Photoelectric current in a photocell increases with increases in frequency, λ1 = hcϕ As per equation,The intensity of light increases, the saturation current increases, This is because a larger number of photons now fall on the metal surface and HENCE a larger number of electrons interact with photons. The number of electrons emitted increases and hence the current increases.B) We know,tanθ= ehc The slope of the photocurrent is same for every surface.C)The maximum kinetic energy of a stream of the photoelectron is determined by the measuring the stopping potential (the applied VOLTAGE needed keep the photoelectrons trapped in the photoemissive surface).Increases linearly with the frequency of the incident light above the threshold frequency is independent of the intensity of the incident light.Explanation:c is the ANSL hope it will help u ☺️ |
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