1.

The sum and product of mean and variance of one binomial distribution is 24 and 128 then parameters of distribution are ………….

Answer»

`((1)/(7) + (1)/(8))^(12)`
`((1)/(4) + (3)/(4))^(12)`
`((1)/(6) + (5)/(6))^(24)`
`((1)/(2) + (1)/(2))^(32)`

Answer :D


Discussion

No Comment Found

Related InterviewSolutions