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The sum and sum of squares corresponding to length x ( in cm) and weight y ( in gm ) of 50 plant products are given below : sum_(i=1)^(50)x_(i)=212, sum_(i=1)^(50)x_(i)^(2)=902.8, sum_(i=1)^(50)y_(i)=261, sum_(i=1)^(50)y_(i)^(2)=1457.6 If C.V._(x) and C.V._(y) are the coefficient of variation of length and weight respectively, then variability in weight is |
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Answer» GREATER than VARIABILITY of length |
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