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The sum of (1^(2)-1+1) (1!)+(2^(2)-2+1)(2!) +...+ (n^(2)-n+1) (n!) is - |
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Answer» `(N+2)!` `=(n^(2)-1)n!-(n-2)n!` `T_(n)=(n-1)(n+1)!-(n-1)n!` SUM `=1+(n-1) (n+1) !` |
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