1.

The Sum Of 3rd And 6th Term Of An A.p Is 27. Find The Sum Of The First 10 Terms Of The Progression?

Answer»

T3 = a + 3D

T6 = a + 6d

T3 + T6 = 2a + 9d = 27

Sum of FIRST 10 terms of an AP is: 

S= (10/2) (2a+9d)

= 5 x 27

= 135

T3 = a + 3d

T6 = a + 6d

T3 + T6 = 2a + 9d = 27

Sum of first 10 terms of an AP is: 

S= (10/2) (2a+9d)

= 5 x 27

= 135



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