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The Sum Of 3rd And 6th Term Of An A.p Is 27. Find The Sum Of The First 10 Terms Of The Progression? |
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Answer» T3 = a + 3D T6 = a + 6d T3 + T6 = 2a + 9d = 27 Sum of FIRST 10 terms of an AP is: S= (10/2) (2a+9d) = 5 x 27 = 135 T3 = a + 3d T6 = a + 6d T3 + T6 = 2a + 9d = 27 Sum of first 10 terms of an AP is: S= (10/2) (2a+9d) = 5 x 27 = 135 |
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