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The sum of a number is 12 and sum of its reciprocal is 3/8 Find the numbers. |
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Answer» If we take numbers as 6 + x, 6 – x \(\frac{1}{6+x}+\frac{1}{6-x}=\frac{3}{8}\) 12 x 8 = 3 (36 - x2), 96 = 108 - 3x2 3x2 = 12x2 = 4, x - 2 or -2 Numbers = 6 + 2 = 8, 6 - 2 = 4 |
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