1.

The sum of coordination number and oxidation number of the metal Min the complex [M(en)_(2)(C_(2)O_(4))]Cl (where en is ethylenediamine) is :

Answer»

7
8
9
6

Solution :`[M(en)_(2)(C_(2)O_(4))]^(+)`. If OXIDATION no. of Mis X, then `x+0+(-2)=+1orx=+3`
As en and `C_(2)O_(4)` are bidentate ligands, coordination no.=6
`therefore` SUM of oxidation no. and coordination no. = 3+6=9


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