The sum of cubes ofthe first n natural numbers is given by _________(a) {n(n+1)/2}^2(b) {n(n-1)/2}^2(c) {n2(n+1)/2}^2(d) None of the mentionedI had been asked this question during an interview.This key question is from Special Sequences topic in chapter Basic Structures: Sets, Functions, Sequences, Sums and Matrices of Discrete Mathematics

The sum of cubes ofthe first n natural numbers is given by _________(a

1.	The sum of cubes ofthe first n natural numbers is given by _________(a) {n(n+1)/2}^2(b) {n(n-1)/2}^2(c) {n2(n+1)/2}^2(d) None of the mentionedI had been asked this question during an interview.This key question is from Special Sequences topic in chapter Basic Structures: Sets, Functions, Sequences, Sums and Matrices of Discrete Mathematics
Answer» Correct CHOICE is (a) {n(n+1)/2}^2 For explanation I WOULD SAY: 1^3 + 2^3 + 3^3 + 4^3 +……+ n^3 = {n(n+1)/2}^2.

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