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The sum of first 16 terms of the AP 10, 6, 2 … isA. 320B. `-320`C. `-352`D. `-400` |
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Answer» Correct Answer - B `l = T_(16) = 10 + 15 xx (-4) = -50` `therefore "sum" = (n)/(2)(a+l) = (16)/(2) (10-50) = 8 xx (-40) = -320.` |
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