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The sum of magnitudes of two forces acting at a point is 16N. If their resultant is normal to the smaller force and has a magnitude of 8N. Then the forces are |
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Answer» SOLUTION :LET `vec(F)` be the resultant of two forces `vec(F)_(1)` and `vec(F)_(2)` as shown in figure with `F_(2) gt F_(1)`. `F_(2) sin theta = F_(1)` ….(i) `F_(2) cos theta = F = 8` …..(ii) Squaring and adding EQS (i) and (ii), we get `F_(2)^(2) = F_(1)^(2) + 64`.....(iii) Given `F_(1) + F_(2) = 16`.....(iv) SolvingEqs. (iii) and (iv), we get `F_(1) = 6N` and `F_(2) = 10 N` |
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