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The sum of n terms of an A.P. is 2n + 3n2. Which term of this A.P. is equal to 299?(a) 11th (b) 50th (c) 35th (d) 29th

Answer»

Answer: (b) 50th 

Sn = 3n2 + 2n 

∴ Sn –1 = 3(n – 1)2 + 2(n – 1) 

= 3n2 – 6n + 3 + 2n – 2 = 3n2 – 4n + 1 

∴ Tn = Sn – Sn – 1 = (3n2 + 2n) – (3n2 – 4n + 1) = 6n – 1. 

Given, Tn = 299 

⇒ 6n – 1 = 299 

⇒ 6n = 300 

n = 50.



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