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The sum of square ofthe first n natural numbers isgiven by _________(a) n(n+1)(2n+1)/6(b) n(n-1)/2(2n+1)(c) n^2(n+1)(2n+1)/6(d) None of the mentionedI got this question in examination.This interesting question is from Special Sequences topic in chapter Basic Structures: Sets, Functions, Sequences, Sums and Matrices of Discrete Mathematics

Answer»

The CORRECT CHOICE is (a) N(n+1)(2n+1)/6

The EXPLANATION: 1^2 + 2^2 + 3^2 + 4^2 +……n^2 = n(1+n)(2n+1)/6.



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