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The sum of squares of first n natural numbers is given by 16n(n+1)(2n+1) or 16(2n3+3n2+n). Find the sum of squares of the first 10 natural numbers. |
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Answer» The sum of squares of first n natural numbers is given by 16n(n+1)(2n+1) or 16(2n3+3n2+n). Find the sum of squares of the first 10 natural numbers. |
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