The Sum Of The Ages Of A Father And Son Is 45 Years Five Years Ago Th

1.	The Sum Of The Ages Of A Father And Son Is 45 Years Five Years Ago The Product Of Their Ages Was 4 Times The Father's Age At That Time. The Present Ages Of The Father And Son Respectively Are?
Answer» Present ages of father and SON be x years and (45-x) years (x -5)(45 –x -5) = 4(x -5) -x2 +41x -180 =0 or x =36. Therefore, present ages of father and son are 36 years and 9 years. Present ages of father and son be x years and (45-x) years (x -5)(45 –x -5) = 4(x -5) -x2 +41x -180 =0 or x =36. Therefore, present ages of father and son are 36 years and 9 years.

The Sum Of The Ages Of A Father And Son Is 45 Years Five Years Ago The Product Of Their Ages Was 4 Times The Father's Age At That Time. The Present Ages Of The Father And Son Respectively Are?

Answer»

Present ages of father and SON be x years and (45-x) years

(x -5)(45 –x -5) = 4(x -5)

-x2 +41x -180 =0 or x =36.

Therefore, present ages of father and son are 36 years and 9 years.

Present ages of father and son be x years and (45-x) years

(x -5)(45 –x -5) = 4(x -5)

-x2 +41x -180 =0 or x =36.

Therefore, present ages of father and son are 36 years and 9 years.