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The Sum Of The Ages Of A Mother And Her Son Is 45 Years. Five Years Ago, The Product Of Their Ages Was 3 Times The Mother Age At That Time, Then The Present Age Of The Son? |
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Answer» LET's assume MOTHER age = x years. ----- (1) sum of mother and her son age = 45 so son age will be = (45-x) years. ------- (2) Five year ago: mother age will be = (x-5) years son age will be = (45-x-x) years = (40-x) year. As PER question (x-5) * (40-x) = 3*(x-5) => (40-x) = 3 => x = 37 year. so son age will be (45-37) = 8 years. Let's assume mother age = x years. ----- (1) sum of mother and her son age = 45 so son age will be = (45-x) years. ------- (2) Five year ago: mother age will be = (x-5) years son age will be = (45-x-x) years = (40-x) year. As per question (x-5) * (40-x) = 3*(x-5) => (40-x) = 3 => x = 37 year. so son age will be (45-37) = 8 years. |
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