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The sum of the areas of two squares is 468 m2. If the difference of their perimeters is 24 m, find the sides of the two squares |
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Answer» The sides of the first square and the second square, whose sum of the areas is 468 m2and thedifference of their perimeters is 24m, is 18m and12m respectively A perimeter is defined as the total length of the boundaries of a square |
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