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The sum of the base angles of a triangle is 130° and their difference is 40°. Find the measures of all its angles. |
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Answer» Suppose base angles are B and C According to problem ∠B + ∠C = 130° (given) ∠B – ∠C = 40° (given) ⇒ 2 ∠B = 170° ⇒ ∠B = 85° ∠C = 130° – 85° = 45° Hence, ∠B = 85°, ∠C = 45° and ∠A = 50°. |
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