1.

The sum of the base angles of a triangle is 130° and their difference is 40°. Find the measures of all its angles.

Answer»

Suppose base angles are B and C

According to problem

∠B + ∠C = 130° (given)

∠B – ∠C = 40° (given)

⇒ 2 ∠B = 170°

⇒ ∠B = 85°

∠C = 130° – 85° = 45°

Hence, ∠B = 85°, ∠C = 45° and ∠A = 50°.



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