1.

The sum of the digits of a two-digit number is 12. If the new number formed by reversing the digits is greater than the original number by 18, find the original number.

Answer»

Let, the unit’s digit = x

The ten’s digit = 12 – x

∴ The number = 10(12 – x) + x = 120 – 9x

After reversing,

Unit’s digit = 12 – x

Ten’s digit = x

∴The number after reversing = 10x + 12 – x = 9x + 12

According to problem,

⇒ 9x + 12 = 120 – 9x + 18

⇒ 18x = 126

⇒ x = 7

∴ The original number,

⇒ 120 – 9 × 7

⇒ 57



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