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The sum of the digits of a two-digit number is 12. If the new number formed by reversing the digits is greater than the original number by 18, find the original number. |
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Answer» Let, the unit’s digit = x The ten’s digit = 12 – x ∴ The number = 10(12 – x) + x = 120 – 9x After reversing, Unit’s digit = 12 – x Ten’s digit = x ∴The number after reversing = 10x + 12 – x = 9x + 12 According to problem, ⇒ 9x + 12 = 120 – 9x + 18 ⇒ 18x = 126 ⇒ x = 7 ∴ The original number, ⇒ 120 – 9 × 7 ⇒ 57 |
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