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The sum of the infite series `(1/3)^(2)+1/3(1/3)^(4)+1/5(1/3)^(6)`+……..isA. `1/4log_(e)2`B. `1/2log_(e )2`C. `1/6 log_(e ) 2`D. `1/4 log_(e )3/2` |
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Answer» Answer: We have `(1/2)^(2)+1/3^(4)+1/5^(1)(3)^(6)`+… `=1/3{(1/3+1/3(1/3)^(3)+1/5(1/3)^(5)+…)}` `1/3xx1/2log(1+(1))/(3)(12-(1))/(3) before x+(x^(3))/(3)+(x^(5))/(5)+..=1/2 log(1+x)/(1-x)` `=1/6log2` |
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