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The sum of the series (.^(101)C_(1))/(.^(101)C_(0)) + (2..^(101)C_(2))/(.^(101)C_(1)) + (3..^(101)C_(3))/(.^(101)C_(2)) + "….." + (101..^(101)C_(101))/(.^(101)C_(100)) is "____". |
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Answer» `:.` Given sum `= underset(r=1)overset(101)sum(102-r)` `= 101+100+99+"...."+2+1` `=5151` |
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