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The sum of the series `5/(1. 2.3)+7/(3. 4.5)+9/(5. 6.7)+` ....is equal toA. `log(8//e)`B. `log(e//8)`C. log 8eD. log 8 |
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Answer» Answer: We have `(5)/(1.2.3)+(7)/(3.4.5)+(9)/(5.6.7)`+… `=underset(n=1)overset(infty)Sigma((2n+3)/(2n-1)(2n)(2n+1))` Let `(2n+3)/((2n-1)(2n)(2n+1)=(A)/(2n-1)+(B)/(2n)+(C )/(2n+1)`.Then `A=(1+3)/(1xx(1+1)=2` `B=(0+3)/((0-1)(0+1))=-3` `C=(-1+3)/((-1)-1)(-1)=1` `therefore (2n+3)/((2n-1)(2n)(2n+1))=2((1)/(2n-1)-(1)/(2n))-((1)/(2n)-(1)/(2n+1))` `rarr underset(n=1)overset(infty)Sigma(2n+3)/((2n-1)(2n)(2n+1))` `=2log 2 + log2-1=3 log2-loge=log(8//e)` |
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