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The sum of the series `((a-b)/(a))+1/2((a-b)/(a))^(2)+1/3((a-b)/(a))^(3)+….infty` isA. `log_(a)(b)`B. `log_(a-b)(a)`C. `log_(b)(a)`D. `log_(a-b)(b)` |
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Answer» Answer: We have `(a-b)/(a)+1/2(a-b)/(a)^(2)+1/3((a-b)/(a))^(3)+…infty` `={-((a-b)/(a)-1/2(a-b)/(a))^(2)-1/3((a-b)/(a))^(3)-…infty}` `=-log_(e )(b/a)=log_(e )(a/b)` |
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