1.

The sum of the series `((a-b)/(a))+1/2((a-b)/(a))^(2)+1/3((a-b)/(a))^(3)+….infty` isA. `log_(a)(b)`B. `log_(a-b)(a)`C. `log_(b)(a)`D. `log_(a-b)(b)`

Answer» Answer:
We have
`(a-b)/(a)+1/2(a-b)/(a)^(2)+1/3((a-b)/(a))^(3)+…infty`
`={-((a-b)/(a)-1/2(a-b)/(a))^(2)-1/3((a-b)/(a))^(3)-…infty}`
`=-log_(e )(b/a)=log_(e )(a/b)`


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