The sum of three consecutive multiples of 8 is 888. Find the multiples

1.	The sum of three consecutive multiples of 8 is 888. Find the multiples.
Answer» Let the three consecutive multiples of 8 be 8x, 8(x + 1), 8(x + 2). Sum of these numbers = 8x + 8(x + 1) + 8(x + 2) = 888 8(x + x + 1 + x + 2) = 888 8(3x + 3) = 888 On dividing both sides by 8, we obtain 8( 3x + 3)/8 = 888/8 3x + 3 = 108 On transposing 3 to R.H.S, we obtain 3x = 111 − 3 3x = 108 On dividing both sides by 3, we obtain 3x/3 = 108/3 x = 36 First multiple = 8x = 8 × 36 = 288 Second multiple =8(x + 1) = 8 x (36 + 1) = 8 x 37 = 296 Third multiple = 8(x + 2) = 8 × (36 + 2) = 8 × 38 = 304 Hence, the required numbers are 288, 296, and 304.

The sum of three consecutive multiples of 8 is 888. Find the multiples.

Answer»

Let the three consecutive multiples of 8 be 8x, 8(x + 1), 8(x + 2).

Sum of these numbers = 8x + 8(x + 1) + 8(x + 2) = 888

8(x + x + 1 + x + 2) = 888

8(3x + 3) = 888

On dividing both sides by 8, we obtain

8( 3x + 3)/8 = 888/8

3x + 3 = 108

On transposing 3 to R.H.S, we obtain

3x = 111 − 3

3x = 108

On dividing both sides by 3, we obtain

3x/3 = 108/3

x = 36

First multiple = 8x = 8 × 36 = 288

Second multiple =8(x + 1) = 8 x (36 + 1) = 8 x 37 = 296

Third multiple = 8(x + 2) = 8 × (36 + 2) = 8 × 38 = 304

Hence, the required numbers are 288, 296, and 304.