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the sum of three consecutive terms in an AP is 6 & their product is -120 find the three terms |
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Answer» Let the consecutive terms in AP be a-d, a and. a+d So by 1st condition a-d+a+a+d=6 =>a=2 By 2nd condition (a--d)×a×(a+d)=-120 =>2(4-d^2)=-120 =>d^2=64 =>d=+8or-8 So three terms are -6,2,10 Or 10,2,-6 |
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