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The sum of three expressions is 8 + 13a + 7a2. Two of them are 2a2 + 3a + 2 and 3a2 – 4a + 1. Find the third expression. |
Answer» Given that f he sum of 3 expressions is 8 + 13a + 7a2 ……………..(1) Two of them are 2a2 + 3a + 2 and 3a2 – 4a + 1. ∴ The sum of above two expressions (2a2 + 3a + 2) + (3a2 – 4a + 1) = 2a2 + 3a + 2 + 3a2 – 4a + 1. = (2a2 + 3a2) + (3a – 4a) + (2 + 1) = 5a2 – a + 3 ∴ The required 3rd expression (1) – (2) (1) – (2) =(7a2 + 13a + 8) – (5a2 – a + 3) = 7a2 + 13a + 8 – – 5a2 – a – 3 =(7a2 – 5a2) +(13a + a)+ (8 – 3) = 2a2 + 14a + 5 |
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