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The sum of three numbers is 58. The second number is three times of two-fifth of the first number and the third number is 6 less than the first number. Find the three numbers. |
Answer» Here what we know a + b + c = 58 (sum of three numbers is 58) Let the first number be ‘x’ b = a + 3 (the second number is three times of 12 of the first number) b = 3 x 2/5x = 6/5x Third number = x – 6 Sum of the numbers is given as 58. ∴ x + 6/5x + (x – 6) = 58 Multiplying by 5 throughout, we get 5 × x + 6x + 5 × (x – 6) = 58 x 5 5x + 6x + 5x – 30 = 290 ∴ 16x = 290 + 30 ∴ 16x = 320 ∴ x = 320/16x = 20 Answer: 1st number =20 2nd number = 3 x 25 x 20 = 24 3rd number = 24 – 6 = 14 |
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