1.

The sum of three numbers is 58. The second number is three times of two-fifth of the first number and the third number is 6 less than the first number. Find the three numbers.

Answer»

Here what we know

a + b + c = 58 (sum of three numbers is 58)

Let the first number be ‘x’

b = a + 3 (the second number is three times of 12 of the first number)

b = 3 x 2/5x = 6/5x

Third number = x – 6

Sum of the numbers is given as 58.

∴ x + 6/5x + (x – 6) = 58

Multiplying by 5 throughout, we get

5 × x + 6x + 5 × (x – 6) = 58 x 5

5x + 6x + 5x – 30 = 290

∴ 16x = 290 + 30

∴ 16x = 320

∴ x = 320/16x = 20

Answer:

1st number =20

2nd number = 3 x 25 x 20 = 24

3rd number = 24 – 6 = 14



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