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The sum of two numbers is 48 and their product is 432. Find the numbers. |
Answer» Let the numbers be ‘a’ and ‘b’. Given, sum of two numbers is 48 and their product is 432. ⇒ a + b = 48 ⇒ a = 48 – b Also, ab = 432 ⇒ 48b – b2 = 432 ⇒ b2 – 48b + 432 = 0 ⇒ b2 – 36b – 12b + 432 = 0 ⇒ b(b – 36) – 12(b – 36) = 0 ⇒ (b – 12)(b – 36) = 0 ⇒ b = 12, 36 |
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