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The sum of two numbers is 80. The larger number exceeds four times the smaller one by 5. Find the numbers. |
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Answer» Let the smaller number is x and larger number is y. Given that sum of both numbers is 80. ∴ x + y = 80. ... (1) Given that the larger number exceeds four times the smaller one by 5. ∴ y = 4x +5. ... (2) By putting y = 4x + 5 in equation (1), we get x + (4x +5) = 80. ⇒ 5x = 80 – 5 = 75 ⇒ x = \(\frac{75}{5}\) = 15. Now, putting x = 15, in equation (2), we get y = 4 × 15 + 5 = 60 + 5 = 65. Hence, the numbers are 15 and 65. |
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