The sums of first and second ionization energies and those of third and fourth ionization energies ("in kJ mol"^(-1)) of nickel and platinum are: {:(,(IE_(1)),(IE)_(2)),(,Ni,2.49),(,Pt,2.66):} {:(,(IE_(1)),(IE)_(2)),(,Ni,8.80),(,Pt,6.70):} Justify using above data why Ni^(+2) and Pt^(+4) are more stable than their corresponding counter part ions ?

The sums of first and second ionization energies and those of third an

1.	The sums of first and second ionization energies and those of third and fourth ionization energies ("in kJ mol"^(-1)) of nickel and platinum are: {:(,(IE_(1)),(IE)_(2)),(,Ni,2.49),(,Pt,2.66):} {:(,(IE_(1)),(IE)_(2)),(,Ni,8.80),(,Pt,6.70):} Justify using above data why Ni^(+2) and Pt^(+4) are more stable than their corresponding counter part ions ?
Answer» Solution :Comparing `IE_1 + IE_2` and Ni and Pt, Ni has LOWER VALUE than Pt THEREFORE,`Ni^(+2)` will be more STABLE than `Pt^(+2)` where as on summating`IE_1, IE_2 , IE_3 and IE_4 . ` `Ni^(4+)=2.49+8.80=11.29` `Pt^(4+)=2.66+6.70=9.36` I.E. of Pt (IV) is LESS than Ni(V) Therefore `Pt^(4+)` is more stable