1.

The surface area of a rectangular film of a liquid is extended from 10 cm xx" 6 cm to 12 m" xx 10 cm. If the work done during this process is 6 xx 10^(-4)J and surface tension of liquid is n xx 10^(-2)" N/cm", find the value of n.

Answer»

Solution :`triangleA=` INCREASE of area
`=2(12 xx 10-10 xx 6)cm^(2)`
`=120cm^(2)=120 x 10^(-4) m^(2)`
Surface tension `=("WORK DONE")/("Increase in area")`
`=(6 xx 10^(-4))/(120 xx 10^(-4))`


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