The surface tension and vapour pressure of water at `20^(@)C` is `7.28xx10^(-2)Nm^(-1)` and `2.33xx10^(3)Pa`, respectively. What is the radius of the smallest spherical water droplet which can form without evaporating at `20^(@)C`?

The surface tension and vapour pressure of water at `20^(@)C` is `7.28

1.	The surface tension and vapour pressure of water at `20^(@)C` is `7.28xx10^(-2)Nm^(-1)` and `2.33xx10^(3)Pa`, respectively. What is the radius of the smallest spherical water droplet which can form without evaporating at `20^(@)C`?
Answer» Given, surface tension of water `" "(S)=7.28xx10^(-2) N//m` Vapour pressure (p) `=2.33xx10^(3)` Pa The drop will evaporate, if the water pressure is greater than the vapour pressure. Let a water droplet or radius R can be formed without evaporating. Vapour pressure=Excess pressure in drop. `therefore p=(2S)/(R)` or `R=(2S)/(p)=(2xx7.28xx10^(-2))/(2.33xx10^(3))` `=6.25xx10^(-5)` m

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The surface tension and vapour pressure of water at `20^(@)C` is `7.28xx10^(-2)Nm^(-1)` and `2.33xx10^(3)Pa`, respectively. What is the radius of the smallest spherical water droplet which can form without evaporating at `20^(@)C`?

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