1.

The surface tension of a soap solution is 30xx10^(-3)Nm^(-1). The work done in stretching a bubble of this solution of surface area 5cmxx5cm, to an area of 10cmxx10cm, is

Answer»

`4.5xx10^(-4)J`
`6.0xx10^(-4)J`
`4.5xx10^(-5)J`
`7.5xx10^(-4)J`

SOLUTION :Work done.
`=2(A_(2)-A_(1))xxS`
`=2(10xx10-5xx5)xx10^(-4)m^(2)xx30xx10^(-3)NM^(-1)`
`=4.5xx10^(-5)J`.


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