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The surface tension of a soap solution is 30xx10^(-3)Nm^(-1). The work done in stretching a bubble of this solution of surface area 5cmxx5cm, to an area of 10cmxx10cm, is |
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Answer» `4.5xx10^(-4)J` `=2(A_(2)-A_(1))xxS` `=2(10xx10-5xx5)xx10^(-4)m^(2)xx30xx10^(-3)NM^(-1)` `=4.5xx10^(-5)J`. |
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