1.

The surface tension of a soap solution is `30xx10^(-3)Nm^(-1)`. The work done in stretching a bubble of this solution of surface area `5cmxx5cm`, to an area of `10cmxx10cm`, isA. `4.5xx10^(-4)J`B. `6.0xx10^(-4)J`C. `4.5xx10^(-5)J`D. `7.5xx10^(-4)J`

Answer» Correct Answer - A
Work done.
`=2(A_(2)-A_(1))xxS`
`=2(10xx10-5xx5)xx10^(-4)m^(2)xx30xx10^(-3)Nm^(-1)`
`=4.5xx10^(-5)J`.


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