The system as shown in fig is released from rest. Calculate the tension in the strings and force exerted by the strings on the pulley. Assuming pulleys and strings are massless

The system as shown in fig is released from rest. Calculate the tensio

1.	The system as shown in fig is released from rest. Calculate the tension in the strings and force exerted by the strings on the pulley. Assuming pulleys and strings are massless
Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`T_(1)-1g=1a"____(1)"` <br/> `T_(2)-T_(1)=3a"____(2)"` <br/> `2g-T_(2)=<a href="https://interviewquestions.tuteehub.com/tag/2a-300249" style="font-weight:bold;" target="_blank" title="Click to know more about 2A">2A</a>"____(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)"` <br/> Solving the above equations, <br/> we get, `a=(g)/(6)m//s^(2)` <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/NAR_NEET_PHY_XI_P2_C05_SLV_031_S01.png" width="80%"/> <br/> `T_(1)=(7g)/(6)N, T+(2)=(5g)/(3)N` <br/> <a href="https://interviewquestions.tuteehub.com/tag/force-22342" style="font-weight:bold;" target="_blank" title="Click to know more about FORCE">FORCE</a> on pulley `P_(1)` is `F_(1)=sqrt(T_(1)^(2)+T_(1)^(2))` <br/> `=sqrt2T_(1)=(7g)/(3sqrt2)N` <br/> Force on pulley `P_(2)` is `F_(2)=sqrt(T_(2)^(2)+T_(2)^(2))` <br/> `=sqrt2T_(2)=(5sqrt2g)/(3)N`</body></html>