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The system in Fig. is released from rest from the position shown. After blocks have moved distance `H//3`. collar `B` is removed and block `A` and `C` continue to move. The speed of `C` just before it strikes the ground is A. `4/3sqrt(gH)`B. `2(sqrt(gH))/3`C. `sqrt((13gH))/3`D. `2sqrt(2gH)` |
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Answer» Correct Answer - C Initial acceleration of the system before the collar is removed. `a_(1)=(2mg)/(3m)=(2g)/3` velocity at the time when the collar is removed: `v_(1)=sqrt(2a_(1)H/3)` Acceleration after the collar is removed `a_(2)=(mg)/(2m)=g/2` Final velocity `=v_(2)^(2)=v_(1)^(2)+2a_(2)H` `=(2a_(1)H)/3+(2g)/2H=2/3 (2g)/3H+gH` `implies v_(2)=sqrt((13gH)/3` |
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