1.

The system is released from rest with the spring initially stretched 75 mm. Calculate the velocity of the block after it has dropped 12 mm. The spring has a stiffness of 1050 Nm^(-1). Neglect the mass of the small pulley. 

Answer»

`0.371 MS^(-1)`
`0.45 ms^(-1)`
`5 ms^(-1)`
`2.2 m s^(-1)`

ANSWER :A


Discussion

No Comment Found