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The system ` kx - y = 2 and 6x - 2y = 3` has a unique solution only whenA. ` k = 0 `B. ` k ne 0 `C. ` k =3 `D. ` k ne 3 ` |
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Answer» Correct Answer - D For a unique solution, we have ` (a_1)/(a_2) ne (b_1)/(b_2 ) ` . ` therefore (k)/(6) ne (-1)/(2) rArr k ne 3`. |
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