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The system shown in the figure is in equilibrium at rest . The spring and string are massless Now the string is cut . Find the acceleration of the blocks just after the string is cut |
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Answer» Solution :Under equilibrium of MASS m T= mg. Now the string is CUT , Therefore T=mg FORCE is decreased on mass m upwards and downwards on mass 2m. `:.` Acceleration of `(mg)/m=g` Acceleration of `2m=(3mg-2mg)/(2m)=g/2`
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